# Line slope calculator 2x-3y=-16

**Straight line given by points A[1; 6] and B[4; 8]**

## Calculation:

**Slope-intercept form of line:**y = 0.6667x+5.3333

**Canonical form of the line equation:**2x-3y+16 = 0

**Parametric form of the line equation:**

x = 3t+1

y = 2t+6 ; t ∈ R

**Slope:**m = 0.6667

**Slope angle of line: φ =**33°41'24″ = 0.588 rad

**X intercept:**x

_{0}= -8

**Y intercept:**y

_{0}= q = 5.3333

**Distance line from the origin:**d

_{0}= 4.4376

**The length of the segment AB: |AB| =**3.6056

**Vector: AB =**(3; 2)

**Normal vector: n =**(2; -3)

**Midpoint of the segment AB: M =**[2.5; 7]

**Perpendicular Bisector equation:**3x+2y-21.5 = 0

**Vector OA = (1; 6) ; |OA| = 6.0828**

**Vector OB = (4; 8) ; |OB| = 8.9443**

**Scalar product OA .OB = 52**

**Angle ∠ AOB = 17°6'10″ = 0.2985 rad**